t^2+2t+12=0

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Solution for t^2+2t+12=0 equation: 



t^2+2t+12=0

a = 1; b = 2; c = +12;
Δ = b2-4ac
Δ = 22-4·1·12
Δ = -44
Delta is less than zero, so there is no solution for the equation

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